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Information for RPM python-pycurl-7.45.1-5.ocs23.src.rpm

ID55759
Namepython-pycurl
Version7.45.1
Release5.ocs23
Epoch
Archsrc
SummaryA Python interface to libcurl
DescriptionPycURL is a Python interface to libcurl, the multiprotocol file transfer library. Similarly to the urllib Python module, PycURL can be used to fetch objects identified by a URL from a Python program.
Build Time2023-09-19 09:40:14 GMT
Size244.54 KB
3e91bbcb6293e09af809ab4d10f55fa0
LicenseLGPLv2+ or MIT
Buildrootdist-ocs23-python311-build-87383-5050
Provides
python-pycurl-debuginfo = 7.45.1-5.ocs23
python-pycurl-debugsource = 7.45.1-5.ocs23
python3-pycurl = 7.45.1-5.ocs23
Obsoletes No Obsoletes
Conflicts No Conflicts
Requires
gcc
libcurl-devel
make
openssl-devel
python3-devel
python3-setuptools
rpmlib(CompressedFileNames) <= 3.0.4-1
rpmlib(FileDigests) <= 4.6.0-1
vsftpd
Recommends No Recommends
Suggests No Suggests
Supplements No Supplements
Enhances No Enhances
Files
1 through 4 of 4
Name ascending sort Size
0001-python-pycurl-7.45.1-tls-backend.patch3.95 KB
0002-python-pycurl-7.45.1-curl-7.83-compatibility.patch1.80 KB
pycurl-7.45.1.tar.gz228.40 KB
python-pycurl.spec2.91 KB
Component of No Buildroots